![]() So you can rewrite 7 x as 2 x + 5 x, and continue factoring as in the example above. Do either of these pairs have a sum of 7? Yes, 2 and 5. Look at factor pairs of 10: 1 and 10, 2 and 5. The resulting factors will be ( x + r) and ( x + s).įor example, to factor x 2 + 7 x +10, you are looking for two numbers whose sum is 7 (the coefficient of the middle term) and whose product is 10 (the last term). Rewrite the trinomial as x 2 + rx + sx + c and then use grouping and the distributive property to factor the polynomial. To factor a trinomial in the form x 2 + bx + c, find two integers, r and s, whose product is c and whose sum is b. Fortunately, there's a rule for that.įactoring Trinomials in the form x 2 + bx + c If you rewrite 7 x as 6 x + x, this method won’t work. How do you know how to rewrite the middle term? Unfortunately, you can’t rewrite it just any way. Group the pairs and factor out the common factor x from the first pair and 2 from the second pair. Rewrite the middle term 7 x as 5 x + 2 x.
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